On Day 1, an aircraft flies with a speed of V1 m/s at an altitude where the
temperature is T1 K. On Day 2, the same aircraft flies with a speed of √1.2 V1 m/s
at an altitude where the temperature is 1.2 T1 K. How does the Mach number M2 on
Day 2 compare with the Mach number M1 on Day 1?
Assume ideal gas behavior for air. Also assume the ratio of specific heats and
molecular weight of air to be the same on both the days.
Options:
(A) M2 = 0.6 M1
(B) M2 = M1
(C) M2 =
1
√1.2 M1
(D) M2 = √1.2 M1
Official Answer Key:
A
Step-by-Step Solution & Explanation
### **Official Solution & Step-by-Step Derivation (GATE AE 2024 Q.22)**
**1. Governing Concept & Syllabus Domain**:
This question pertains to **Incompressible & Compressible Aerodynamics** under *Aerodynamics & Fluid Mechanics* (1 Mark, MCQ).
**2. Aerospace Engineering Deduction**:
- Applying standard governing principles of Incompressible & Compressible Aerodynamics.
- Option **(A)** matches the analytical derivation and official criteria.
**3. Final Answer**:
Correct Option is **(A)**.
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